c语言简单运用简单运用

#include <stdio.h>
#define N 20
typedef struct
{
    char no[10];
    int score;
}RECORD;

int find(RECORD a[], int n,RECORD b[]);

int main()
{
    RECORD x[N],y[N];
    int n,i,k;
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {
        scanf("%s",x[i].no);
        scanf("%d",&x[i].score);
    }
    k=find(x,n,y);
    for(i=0;i<k;i++)
        printf("%s %d\n",y[i].no,y[i].score);
    return 0;
}

/* 请在这里填写答案 */

#include <stdio.h>
#define N 20
typedef struct
{
    char no[10];
    int score;
}RECORD;

int find(RECORD a[], int n, RECORD b[]);

int main()
{
    RECORD x[N], y[N];
    int n, i, k;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
    {
        scanf("%s", x[i].no);
        scanf("%d", &x[i].score);
    }
    k = find(x, n, y);
    for (i = 0; i < k; i++)
        printf("%s %d\n", y[i].no, y[i].score);
    return 0;
}

/* 请在这里填写答案 */
int find(RECORD a[], int n, RECORD b[])
{
    int i = 0, j = 0;
    for (i = 0; i < n; ++i) {
        if (a[i].score >= 60 && a[i].score < 80) {
            b[j++] = a[i];
        }
    }
    return j;
}

运行结果

int find(RECORD a[], int n, RECORD b[])
{
    int m = 0;
    for (int i = 0; i < n; i++)
    {
        if (a[i].score >= 60 && a[i].score <= 79)
            b[m++] = a[i];
    }
    return m;
}

• 这有个类似的问题, 你可以参考下: https://ask.csdn.net/questions/7590258
• 你还可以看下c语言参考手册中的 c语言-exp()