给出0～9数字，让他们+-x÷自由运算，如何筛选=1的式子？

给出0～9数字，让他们+-x÷自由运算，如何筛选=1的式子？

K = '''0,1,2,3,4,5,6,7,8,9'''
n = '''+-x÷'''

# 筛选=1
print：

'''
3-2=1,
5-4=1,
3-2-0=1
........
'''

import itertools as it

a = '0123456789'
b = '+-*/'
Exp,Exp1,Exp2 = [],[],[]

for exp in it.product(a,b,a):
    try:
        if exp[0]!=exp[-1] and eval(''.join(exp))==1:
            Exp1.append(''.join(exp))
    except:
        pass


for exp in it.product(a,b,a,b,a):
    try:
        if exp[0]!=exp[2]!=exp[-1] and exp[0]!=exp[-1] and eval(''.join(exp))==1:
            Exp2.append(''.join(exp))
    except:
        pass

for exp in Exp1 + Exp2:
    Exp.append(exp+'=1')

for exp in Exp2:
    Exp.append(exp+'=1')
    
print(len(Exp))

for exp in Exp:
    print(exp)

if 计算结果==1

    number = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '0']
    operator = ['+', '-', '*', '/']
    result = []
    for i in range(int(input("请输入随机生成的算式个数:"))):
        arithmetic = random.choice(number) + random.choice(operator) + random.choice(number)
        try:
            rs = str(round(eval(arithmetic), 2))
        except:
            pass
        print(arithmetic + "=" + rs)
        if rs == '1' or rs == '1.0':
            result.append(arithmetic + "=" + rs)
    print("结果等于1的算式：")
    if len(result) == 0:
        print("没有")
    else:
        for i in result:
            print(i)