用if语句编程序,输入x后按下式计算y值,并输出结果。y=x+2xx+10 0≤x≤8 y=x-3xx*x-9 x<0或x>8
#include <cstdio>
int main()
{
int x, y;
scanf("%d", &x);
if (x >= 0 && x <= 8)
{
y = x + 2 * x * x + 10;
}
else
{
y = x - 3 * x * x * x - 9;
}
printf("y=%d", y);
return 0;
}