输入两个整数a,b计算a和b之间能被4或6整除的数的个数

输入两个整数a,b计算a和b之间能被4或6整除的数的个数

#include<stdio.h>
int main()
{
    int a,b;
int count = 0;
    scanf("%d %d",&a,&b);
    for(int i = a;i <= b;i++){
        if(i % 4 == 0 || i % 6 == 0){
  count++;
            //printf("%d ",i);
        }
    }
printf("%d ",count);
    return 0;
}

public string CheckNums(int a, int b)
{
string result = "";
for (int i = a; i <= b; i++)
{
if (i % 4 == 0 && i % 6 == 0)
{
if (result == "")
result = i.ToString();
else
result += "," + i.ToString();
}
}
}


int main()
{

    int a, b, cnt = 0;
    cin >> a >> b;
    while (a <= b)
    {
        if (a % 4 == 0 && a % 6 == 0)
            cnt++;
        a++;
    }
    cout << cnt << endl;
    return 0;
}

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