求1+1/2+1/3+…1/n的和

输入一个整数n，n＞0，计算s＝1+1/2+1/3+…1/n的和，是一道python的题

n = eval(input())
sum = 0
for i in range(1,n+1):
  sum = sum + (1 / i)
print(sum)

n = int(input())
sum = 0
for i in range(1, n+1):
    sum += 1/i
print(sum)