#include
int main( )
{
double s,t;
int n;
n = 0;
s = 1;
while(t<=99/100)
{
t = n/n+1;
if(n%2!=0)
t = (n/n+1)*-1;
else
t = (n/n+1)*1;
s=s+t;
n=n++;
printf("%f",s);}
return 0;
}
(n/n+1)会等于0,改成(1.0*n)/(n+1)
(99/100)也会等于0,因为整型与整型计算还是整型,改成99.0/100