#输入的数字只有两位数并且没有错误
#用if和if-else
#举例：
输入10
输出ten
输入38
输出thirty-eight（需要有-）
输入99
输出ninety-nine
dic = {1:'one',2:'two',3:'three',4:'four',5:'five',6:'six',7:'seven',8:'eight',9:'nine',10:'ten',
11:'eleven',12:'twelve',13:'thirteen',14:'fourteen',15:'fifteen',16:'sixteen',17:'seventeen',18:'eighteen',19:'nineteen',
20:'twenty',30:'thirty',40:'forty',50:'fifty',60:'sixty',70:'seventy',80:'eighty',90:'ninety',}
number = int(input(">>>"))
if number <= 20:
print(dic[number])
else:
x, y = divmod(number, 10)
print(dic[x*10] + '-' + dic[y])
def int_to_en(num):
d = { 0 : 'zero', 1 : 'one', 2 : 'two', 3 : 'three', 4 : 'four', 5 : 'five',
6 : 'six', 7 : 'seven', 8 : 'eight', 9 : 'nine', 10 : 'ten',
11 : 'eleven', 12 : 'twelve', 13 : 'thirteen', 14 : 'fourteen',
15 : 'fifteen', 16 : 'sixteen', 17 : 'seventeen', 18 : 'eighteen',
19 : 'nineteen', 20 : 'twenty',
30 : 'thirty', 40 : 'forty', 50 : 'fifty', 60 : 'sixty',
70 : 'seventy', 80 : 'eighty', 90 : 'ninety' }
k = 1000
m = k * 1000
b = m * 1000
t = b * 1000
assert(0 <= num)
if (num < 20):
return d[num]
if (num < 100):
if num % 10 == 0: return d[num]
else: return d[num // 10 * 10] + '-' + d[num % 10]
if (num < k):
if num % 100 == 0: return d[num // 100] + ' hundred'
else: return d[num // 100] + ' hundred and ' + int_to_en(num % 100)
if (num < m):
if num % k == 0: return int_to_en(num // k) + ' thousand'
else: return int_to_en(num // k) + ' thousand, ' + int_to_en(num % k)
if (num < b):
if (num % m) == 0: return int_to_en(num // m) + ' million'
else: return int_to_en(num // m) + ' million, ' + int_to_en(num % m)
if (num < t):
if (num % b) == 0: return int_to_en(num // b) + ' billion'
else: return int_to_en(num // b) + ' billion, ' + int_to_en(num % b)
if (num % t == 0): return int_to_en(num // t) + ' trillion'
else: return int_to_en(num // t) + ' trillion, ' + int_to_en(num % t)
raise AssertionError('num is too large: %s' % str(num))
while True:
nums = eval(input())
print(int_to_en(nums))
NUMBER_CONSTANT = {0:"zero ", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven",
8:"eight", 9:"nine", 10:"ten", 11:"eleven", 12:"twelve", 13:"thirteen",
14:"fourteen", 15:"fifteen", 16:"sixteen", 17:"seventeen", 18:"eighteen", 19:"nineteen" };
IN_HUNDRED_CONSTANT = {2:"twenty", 3:"thirty", 4:"forty", 5:"fifty", 6:"sixty", 7:"seventy", 8:"eighty", 9:"ninety"}
def translateNumberToEnglish(number):
if str(number).isnumeric():
if str(number)[0] == '0' and len(str(number)) > 1:
return translateNumberToEnglish(int(number[1:]));
if int(number) < 20:
return NUMBER_CONSTANT[int(number)];
elif int(number) < 100:
if str(number)[1] == '0':
return IN_HUNDRED_CONSTANT[int(str(number)[0])];
else:
return IN_HUNDRED_CONSTANT[int(str(number)[0])] + "-" + NUMBER_CONSTANT[int(str(number)[1])];
else:
return "数值超过99了"
代码如下，如有帮助请点击一下采纳谢谢：
num=input("请输入一个整数:\n")
def less_Hundred(num):
L1 = ["zero","one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"]
L2 = ["eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen",
"twenty"]
L3 = ["thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]
if int(num)<=10:
return L1[int(num)]
elif 10<int(num)<=20:
return L2[int(num)%10-1]
elif 20<int(num)<30:
return L2[-1]+" "+L1[int(num)%10]
elif 30<=int(num)<100:
return L3[int(num)//10-3]+"-"+L1[int(num)%10]
print(less_Hundred(num))
凑个热闹，换个思路：
nums = [
['','ten'],
['one','eleven'],
['two','twelve','twenty'],
['three','thirteen','thirty'],
['four','fourteen','forty'],
['five','fifteen','fifty'],
['six','sixteen','sixty'],
['seven','seventeen','seventy'],
['eight','eighteen','eighty'],
['nine','nineteen','ninety'],
]
num = input()
if num[0] == '1':
res = nums[int(num[1])][1]
else:
res = nums[int(num[0])][2]+'-'+nums[int(num[1])][0]
print(res.rstrip('-'))