如何在数据库MYSQLi中显示php中的图像？

I want to display images in php from my database using Mysqli. THis is my code in question.php:

    <form class="form-horizontal" role="form" id='login' method="post" action="result.php">

                <?php
                $row = mysqli_query( $conn, "select id,question_name,image from questions where category_id=1 and level_id=1 ORDER BY RAND() LIMIT 10");

                $i = 0;
                $j = 1; $k = 1;
                ?>
                <?php while ( $result = mysqli_fetch_assoc($row) ) {
                     //if ( $i == 0) echo "<div class='cont' id='question_splitter_$j'>";?>
                    <div id='question<?php echo $k;?>' >
                    <p class='questions' id="qname<?php echo $j;?>"> <?php echo $k?>.<?php echo $result['question_name'];?></p>

                     <?php echo "<img src='".$result['image']."'/>";?>
                     <input type="text" name="reponse"   required />
                    <br/>

                    </div>
                    <?php

                          $k++;
                     } ?>   
            </form>

My table is :

But the result is like here:

can you please help me to display my images correctly?

You can do this by base64_encode()ing the binary data to the browser using the data-uri scheme:

<?php echo '<img src="data:image/png;base64,'.base64_encode($result['image']).'" />'; ?>

Alternatively, you can create an image.php script, that takes an ID, and outputs the binary data to the browser directly:

$query = mysqli_query("SELECT * FROM ..."); //**Bind** $_GET['ID'] to the query:
$row = mysqli_fetch_assoc($query);
header('Content-type: image/png');
echo $row['image'];

And in your previous code, access it like:

<?php echo '<img src="image.php?id=', $row['id'], '" />'; ?>