关于#urlib#的问题，如何解决？(标签-python|关键词-urllib)

python爬虫入门，在学习urlopen时遇见了问题，不知道是怎么回事，请大家帮忙看看该如何解决？

代码：

import urllib.request

response = urllib.request.urlopen('https://fszj.foshan.gov.cn')
print(response.status)
print(response.getheaders())
print(response.read())

运行结果：

D:\python练习\venv\Scripts\python.exe D:/python练习/1009.py
Traceback (most recent call last):
  File "D:\python练习\1009.py", line 3, in 
    response = urllib.request.urlopen('https://fszj.foshan.gov.cn')
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 216, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 525, in open
    response = meth(req, response)
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 634, in http_response
    response = self.parent.error(
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 563, in error
    return self._call_chain(*args)
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 496, in _call_chain
    result = func(*args)
  File "C:\Users\VV\AppData\Local\Programs\Python\Python310\lib\urllib\request.py", line 643, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 444: 

Process finished with exit code 1

实在看不懂这一大串是什么意思

import urllib.request
import urllib.parse


headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36 QIHU 360SE"}

req = urllib.request.Request('https://fszj.foshan.gov.cn', headers=headers,method="GET")

response=urllib.request.urlopen(req)
print(response.read().decode("utf-8"))

 
import requests

response = requests.get('https://fszj.foshan.gov.cn')
print(response.status_code)
print(response.headers)
print(response.text)