想用 if item["New_ID"] %2==0 的方式取奇数或者偶数,请问应该怎么写呀
newDf1 = pd.DataFrame(columns=['Time', 'eleCur', 'id'])
for key, item in df1.groupby(['id']):
if item.shape[0] > 20 :
if item["New_ID"] %2==0:
item['id'] = key
newDf1 = pd.concat([newDf1, item])
print(key)
print(item)
newDf1 = pd.DataFrame(columns=['Time', 'eleCur', 'id'])
for key, item in df1.groupby(['id']):
item['id'] = key
if item.shape[0] > 20:
# 如果相同id的组中,行数大于20行的话,就只保留New_ID为偶数的
item = item[item["New_ID"] % 2 == 0]
newDf1 = pd.concat([newDf1, item])
你不是已经写出来了吗,直接加个条件过滤就可以了,不需要写 if
newDf1 = df1[df1['New_ID']%2==0]