纯新生求解，多谢了
问题1:
public class DebugTwo1
{
public static void main(String[] args)
{
int a = 315;
double b = 12.4;
System.out.print("The int is ");
System.out.println(int);
System.out.print("The double is ");
System.out.println(double);
}
}
输出的int和double有问题，具体是什么问题也没看懂quq
问题2:
public class DebugTwo2
// This application performs arithmetic with two integers
{
public static void main(String args[])
{
int a, b;
7 = a;
4 = b;
System.out.println("The sum is '+ a + b'");
System.out.println("The difference is '+ a - b'");
System.out.println("The product is '+ a * b'");
}
}
7和4不是变量
问题3:
public class DebugTwo3
// Demonstrates remainder and output
{
public static void main(String args[])
{
double a = 99, b = 8 ;
int c = 77;
result = a % b;
System.out.println("Divide " + a + " by " + b);
System.out.println("remainder is " + result);
System.out.print("c is a very large number:");
System.out.println(c);
}
}
result不能解析为一个变量
谢谢了
第一个代码：
要打印 变量名 a和b，而不是打印变量类型。
第二个代码：
给变量赋值时，变量名应该在前边。 如a=7
第三个代码：
使用变量时，要先申明变量，如 double result = a % b;
你这三个问题本质上都是同一个问题
就是你根本不知道什么叫变量，变量应该如何定义，以及变量名称应该符合什么标准
回去先看书，不要凭感觉瞎写
问题1
public class DebugTwo1
{
public static void main(String[] args)
{
int a = 315;
double b = 12.4;
System.out.print("The int is ");
System.out.println(a);
System.out.print("The double is ");
System.out.println(b);
}
}
问题2
public class DebugTwo2
// This application performs arithmetic with two integers
{
public static void main(String args[])
{
int a, b;
a=7;
b=4;
System.out.println("The sum is"+ a + b);
System.out.println("The difference is"+ a - b);
System.out.println("The product is "+ a * b);
}
}
问题三 double result
public class DebugTwo3
// Demonstrates remainder and output
{
public static void main(String args[])
{
double a = 99, b = 8 ;
int c = 77;
int result = a % b;
System.out.println("Divide " + a + " by " + b);
System.out.println("remainder is " + result);
System.out.print("c is a very large number:");
System.out.println(c);
}
}