3.5 3.7怎么做用c++语言
3.5代码如下
#include <iostream>
using namespace std;
int main()
{
int today, elapsed;//定义变量类型
cout << "Please enter an integer representing the day of the week today" << endl;
cout << "For example,Monday is 1.In particular,Sunday is 0." << endl;
cout << "Enter today's day : ";//今天周几
cin >> today;
cout << "Enter the number of days elapsed since today : ";//距离今天有几天
cin >> elapsed;
int day;
day = (today + elapsed) % 7;//判断未来是周几
switch (today)//用分支语句判断今天周几
{
case 0: cout << "Today is Sunday" << endl;
break;
case 1: cout << "Today is Monday" << endl;
break;
case 2: cout << "Today is Tuesday" << endl;
break;
case 3: cout << "Today is Wednesday" << endl;
break;
case 4: cout << "Today is Thursday" << endl;
break;
case 5: cout << "Today is Friday" << endl;
break;
case 6: cout << "Today is Saturday" << endl;
break;
}
switch (day)//用分支语句判断未来周几
{
case 0: cout << "The future day is Sunday" << endl;
break;
case 1: cout << "The future day is Monday" << endl;
break;
case 2: cout << "The future day is Tuesday" << endl;
break;
case 3: cout << "The future day is Wednesday" << endl;
break;
case 4: cout << "The future day is Thursday" << endl;
break;
case 5: cout << "The future day is Friday" << endl;
break;
case 6: cout << "The future day is Saturday" << endl;
break;
}
system("pause");
return 0;
}
运行结果如下图
3.7代码如下
#include<stdio.h>
void swap(int* pt1, int* pt2) //交换指针指向值
{
int temp;
temp = *pt1;
*pt1 = *pt2;
*pt2 = temp;
}
void exchange(int* p1, int* p2, int* p3)
{
if (*p1 > *p2) //如果p1指针指向的数大于p2,则交换指针指向值
swap(p1, p2);
if (*p1 > *p3) //同上
swap(p1, p3);
if (*p2 > *p3) //同上
swap(p2, p3);
}
int main()
{
int a, b, c; //定义三个变量
int* p1, * p2, * p3; //定义三个指针
printf("请输入3个整数，整数之间用空格隔开: \n");
scanf("%d %d %d", &a, &b, &c); //输入三个数值
p1 = &a, p2 = &b, p3 = &c; //把a,b,c三个数的地址赋值给对应指针
exchange(p1, p2, p3); //调用函数
printf("%d,%d,%d\n", a, b, c); //将调换后的值顺序输出
int wait = 1;
scanf("%d", &a);
return 0;
}
运行截图如下图
3.5 只需要将指定的天数加上当前星期几，求余7就行了啊
3.7 三个整数比较大小，分别求出最大值和最小值，然后三个数之和减去最大值和最小值就是中间值
稍等写代码
3.7代码：
#include <iostream>
using namespace std;
int minmax(int a,int b,int flag)
{
if(flag == 1)
{
if(a>b)
return a;
return b;
}
else if(a<b)
return a;
return b;
}
int main()
{
int a,b,c;
cin>>a>>b>>c;
int max = minmax(c,minmax(a,b,1),1);
int min = minmax(c,minmax(a,b,0),0);
int mid = a+b+c-max-min;
cout<<min<<" "<<mid<<" "<<max<<endl;
return 0;
}
3.5 代码
#include <iostream>
using namespace std;
int main()
{
char week[][20] = {"Sunday", "Monday", "Tuesday", "Wednesday","Thursday", "Friday", "Saturday"};
int today, days,fday;
cout<<"Enter today's day: ";
cin>>today;
cout<<"Enter the number of days elapsed since today: ";
cin>>days;
fday = (today + days)%7;
cout<<"Today is "<< week[today] <<" and the future day is "<<week[fday]<<endl;
return 0;
}
3.5
#include <iostream>
int main() {
const char *weekdays[] = {"Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday"};
int today, elapsed_days;
std::cout << "Enter today's day: ";
std::cin >> today;
std::cout << "Enter the number of days elapsed since today: ";
std::cin >> elapsed_days;
std::cout << "Today is " << weekdays[today] << " and the future day is "
<< weekdays[(today + elapsed_days) % 7] << '\n';
return 0;
}
3.7
#include <iostream>
int main() {
int a, b, c;
std::cout << "Enter three integers: ";
std::cin >> a >> b >> c;
if (a > b)
std::swap(a, b);
if (a > c)
std::swap(a, c);
if (b > c)
std::swap(b, c);
std::cout << a << " " << b << " " << c << "\n";
return 0;
}
//3.5
#include <iostream>
using namespace std;
int sinceToday(int day,int days)
{
int sum = day + days;
return sum%7;
}
int main() {
//1.输入day和days
//2.使用函数sinceToday(day,days);
//3.根据返回值判断星期几，建议用switch,0-星期日，1-星期一，2-星期二....
return 0;
}
//3.7
#include <iostream>
using namespace std;
int main() {
int a,b,c,tmp;
printf("请输入3个数字：");
scanf("%d%d%d",&a,&b,&c);
if(a<b)//如果a比b小，交换a和b的值，使a存放大的数字
{
tmp=a;
a=b;
b=tmp;
}
if(a<c)//如果a比c小，交换a和c的值，使a存放大的数字
{
tmp=a;
a=c;
c=tmp;
}
if(b<c)//如果b比c小，交换b和c的值，使b存放大的数字
{
tmp=b;
b=c;
c=tmp;
}
printf("按照从大到小的顺序为：%d,%d,%d\n",a,b,c);
return 0;
}