python写一个函数来返回argu2中大于argu1的

我只能写到这里

def gFilter(argu1=0,*argu2)：
   for i in argu2:
        if argu2[i]>argu1:

要求是这样

```python
assert gFilter(2,1,2,3) == (3,)
assert gFilter(*(-1,2,3))== (2,3)
assert gFilter(3,*(0,1,2))  == ()

```

def gFilter(argu1=0, *argu2):
    ret = list()
    for i in range(len(argu2)):
        if argu2[i] > argu1:
            ret.append(argu2[i])
    return tuple(ret)


assert gFilter(2,1,2,3) == (3,)
assert gFilter(*(-1,2,3))== (2,3)
assert gFilter(3,*(0,1,2))  == ()

def gFilter(argu1=0,*argu2):
    return tuple(i for i in argu2 if i>argu1)