1.
clear
clc
syms a1 a2 p b1 b2 t c
eq1=p^2/(sin(a1))^2==(p^2+t^2-2ptcos(c-b1))/(sin(c-b1))^2;
eq2=p^2/(sin(a2))^2==(p^2+t^2-2ptcos(b2-c))/(sin(b2-c))^2;
[t,c]=solve(eq1,eq2)
——matlab 2018b
结果：
t=0
c=0
0是指无解嘛？
2.
clear
clc
syms a1 a2 p b1 b2 t c
eq=(sin(a1)/sin(a2))^2==((sin(c-b1)/sin(b2-c))^2)(p^2+t^2-2ptcos(b2-c))/(p^2+t^2-2pt*cos(c-b1));
[t,c]=solve(eq)
将上述两个方程联立后的方程的解又是不同的
t =
((-(cos(b1)^2sin(a2)^2sin(c)^2 - cos(b2)^2sin(a1)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b2)^2 + cos(c)^2sin(a2)^2sin(b1)^2 + cos(b1)cos(c)^3sin(a1)^2sin(b2)^2 - cos(b2)cos(c)^3sin(a2)^2sin(b1)^2 + cos(b2)^2sin(a1)^2sin(b1)sin(c)^3 - cos(b1)^2sin(a2)^2sin(b2)sin(c)^3 + cos(b1)cos(b2)^2cos(c)sin(a1)^2sin(c)^2 - cos(b1)^2cos(b2)cos(c)sin(a2)^2sin(c)^2 + cos(c)^2sin(a1)^2sin(b1)sin(b2)^2sin(c) - cos(c)^2sin(a2)^2sin(b1)^2sin(b2)sin(c) - 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(c) + 2cos(b2)cos(c)sin(a1)^2sin(b2)sin(c) - 2cos(b1)cos(b2)cos(c)^2sin(a1)^2sin(b2)sin(c) + 2cos(b1)cos(b2)cos(c)^2sin(a2)^2sin(b1)sin(c) + 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(b2)sin(c)^2 - 2cos(b2)cos(c)sin(a1)^2sin(b1)sin(b2)sin(c)^2)(cos(b1)^2sin(a2)^2sin(c)^2 - cos(b2)^2sin(a1)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b2)^2 + cos(c)^2sin(a2)^2sin(b1)^2 - cos(b1)cos(c)^3sin(a1)^2sin(b2)^2 + cos(b2)cos(c)^3sin(a2)^2sin(b1)^2 - cos(b2)^2sin(a1)^2sin(b1)sin(c)^3 + cos(b1)^2sin(a2)^2sin(b2)sin(c)^3 - cos(b1)cos(b2)^2cos(c)sin(a1)^2sin(c)^2 + cos(b1)^2cos(b2)cos(c)sin(a2)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b1)sin(b2)^2sin(c) + cos(c)^2sin(a2)^2sin(b1)^2sin(b2)sin(c) - 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(c) + 2cos(b2)cos(c)sin(a1)^2sin(b2)sin(c) + 2cos(b1)cos(b2)cos(c)^2sin(a1)^2sin(b2)sin(c) - 2cos(b1)cos(b2)cos(c)^2sin(a2)^2sin(b1)sin(c) - 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(b2)sin(c)^2 + 2cos(b2)cos(c)sin(a1)^2sin(b1)sin(b2)sin(c)^2))^(1/2) + sin(a1)^2cos(b1 - c)sin(b2 - c)^2 - sin(a2)^2cos(b2 - c)sin(b1 - c)^2)/(sin(a1)^2sin(b2 - c)^2 - sin(a2)^2sin(b1 - c)^2)
-((-(cos(b1)^2sin(a2)^2sin(c)^2 - cos(b2)^2sin(a1)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b2)^2 + cos(c)^2sin(a2)^2sin(b1)^2 + cos(b1)cos(c)^3sin(a1)^2sin(b2)^2 - cos(b2)cos(c)^3sin(a2)^2sin(b1)^2 + cos(b2)^2sin(a1)^2sin(b1)sin(c)^3 - cos(b1)^2sin(a2)^2sin(b2)sin(c)^3 + cos(b1)cos(b2)^2cos(c)sin(a1)^2sin(c)^2 - cos(b1)^2cos(b2)cos(c)sin(a2)^2sin(c)^2 + cos(c)^2sin(a1)^2sin(b1)sin(b2)^2sin(c) - cos(c)^2sin(a2)^2sin(b1)^2sin(b2)sin(c) - 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(c) + 2cos(b2)cos(c)sin(a1)^2sin(b2)sin(c) - 2cos(b1)cos(b2)cos(c)^2sin(a1)^2sin(b2)sin(c) + 2cos(b1)cos(b2)cos(c)^2sin(a2)^2sin(b1)sin(c) + 2cos(b1)cos(c)sin(a2)^2sin(b1)sin(b2)sin(c)^2 - 2cos(b2)cos(c)sin(a1)^2sin(b1)sin(b2)sin(c)^2)(cos(b1)^2sin(a2)^2sin(c)^2 - cos(b2)^2sin(a1)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b2)^2 + cos(c)^2sin(a2)^2sin(b1)^2 - cos(b1)cos(c)^3sin(a1)^2sin(b2)^2 + cos(b2)cos(c)^3sin(a2)^2sin(b1)^2 - cos(b2)^2sin(a1)^2sin(b1)sin(c)^3 + cos(b1)^2sin(a2)^2sin(b2)sin(c)^3 - cos(b1)cos(b2)^2cos(c)sin(a1)^2sin(c)^2 + cos(b1)^2cos(b2)cos(c)sin(a2)^2sin(c)^2 - cos(c)^2sin(a1)^2sin(b1)sin(b2)^2sin(c) + cos(c)^2sin(a2)^2sin(b1)^2*sin(b2)sin(c) - 2cos(b1)*cos(c)sin(a2)^2sin(b1)sin(c) + 2cos(b2)*cos(c)sin(a1)^2sin(b2)sin(c) + 2cos(b1)cos(b2)cos(c)^2sin(a1)^2sin(b2)sin(c) - 2cos(b1)cos(b2)cos(c)^2sin(a2)^2sin(b1)sin(c) - 2cos(b1)*cos(c)sin(a2)^2sin(b1)*sin(b2)sin(c)^2 + 2cos(b2)*cos(c)sin(a1)^2sin(b1)sin(b2)sin(c)^2))^(1/2) - sin(a1)^2cos(b1 - c)sin(b2 - c)^2 + sin(a2)^2cos(b2 - c)sin(b1 - c)^2)/(sin(a1)^2sin(b2 - c)^2 - sin(a2)^2sin(b1 - c)^2)
c =
1
1
而且为什么
c=
1
1 呢？两个1？