为什么我的"habit"的键盘录入过程怎么直接跳过了

import java.util.Scanner;

//学生类
public class Student{
//姓名，年龄，爱好
private String name;
private int age;
private String habit;

//构造方法
Student(String x,int y,String z){
    this.name = x;
    this.age = y;
    this.habit = z;
}

//返回姓名
public String getPerName(){
    return name;
}

//传入姓名
public void setPerName(String name){
    this.name = name;
}

//返回年龄
public int getPerAge(){
    return age;
}

//传入年龄
public void setPerAge(int aga){
    if(age>0&&age<150){
        this.age = age;
    }
}

//返回爱好
public String getPerHabit(){
    return habit;
}

//传入爱好
public void setPerHabit(String habit){
    this.habit = habit;
}

//main方法
public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    System.out.println("请输入学生姓名：");
    String name = sc.nextLine();
    System.out.println("请输入学生年龄：");
    int age = sc.nextInt();
    System.out.println("请输入学生爱好：");
    String habit = sc.nextLine();
    Student s = new Student(name,age,habit);
    System.out.println("添加成功");
    System.out.println("姓名:"+s.getPerName()+ "\t年龄:"+s.getPerAge()+"\t爱好:"+s.getPerHabit());
}

}

这是sc.nextLine（）和sc.nextInt（）的不同机制，参考https://blog.csdn.net/qq_45822805/article/details/113043291