不直接添加元素，如何通过判断和循环将诸如列表：[0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 1, 0, 2, 3]转化为[0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5]
即有顺序地将数据分组，每一组都是0,1,2,3,4,5，每组缺少的数字补上
temp = [0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 0, 1, 2, 3, 4, 5, 1, 0, 2, 3]
group = int(len(temp)/max(temp))
ret = []
for _ in range(group):
for i in range(max(temp)+1):
ret.append(i)
print(ret)
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