How to make a number 8 digit as standard digit. The number will be get to a user id from database. Example
user_id = 1 // This should should be echo as 00000001
user_id = 11 // This should should be echo as 00000011
user_id = 111 // This should should be echo as 00000111
How can I code this? Please help thanks.
You can use printf function with %08s as the format string:
printf("%08s",$user_id);
If you want to store the result back in the string you can use sprintf as:
$user_id = sprintf("%08s",$user_id);
The format specifier %08s says:
s : Interpret the argument as a string
8 : Print the string left justified within 8 alloted places
0 : Fill the unused places with 0
You could use printf:
printf("%08d", $user_id);
$user_id = str_pad($user_id, 8, "0", STR_PAD_LEFT);
PHP has sprintf:
$user_str = sprintf("%08d", $user_id);
echo $user_str;
You can do with str_pad
echo str_pad($user_id,8,'0',STR_PAD_LEFT);
function leadingZeroes($number, $paddingPlaces = 3) {
return sprintf('%0' . $paddingPlaces . 'd', $number);
}