将Python脚本作为Windows系统服务的问题

我想将一个Python程序或脚本安装为Windows的系统服务，以便其机器重启后也能正常运行。
我参照示例编写了脚本FdbService.py，该脚本代码如下：

import win32serviceutil
import win32service
import win32event
import os,sys
import logging
import inspect
import servicemanager
import winerror

class FdbService(win32serviceutil.ServiceFramework):
svc_name = "FdbService" # 服务名
svc_display_name = "FDB backup Service " # 服务在windows系统中显示的名称
svc_description = "This is a FDB backup service program. " # 服务的描述

def __init__(self, args):
    win32serviceutil.ServiceFramework.__init__(self, args)
    self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
    self.logger = self._getLogger()
    self.run = True

def _getLogger(self):
    logger = logging.getLogger('[FdbService]')
    this_file = inspect.getfile(inspect.currentframe())
    dirpath = os.path.abspath(os.path.dirname(this_file))
    handler = logging.FileHandler(os.path.join(dirpath, "service.log"))
    formatter = logging.Formatter('%(asctime)s %(name)-12s %(levelname)-8s %(message)s')
    handler.setFormatter(formatter)
    logger.addHandler(handler)
    logger.setLevel(logging.INFO)
    return logger

def SvcDoRun(self):
    import time
    self.logger.info("Fdb service is run....")
    while self.run:
        self.logger.info("I am runing....")
        time.sleep(2)

def SvcStop(self):
    self.logger.info("Fdb service is stop....")
    self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
    win32event.SetEvent(self.hWaitStop)
    self.run = False

if name == 'main':
if len(sys.argv) == 1:
try:
evtsrc_dll = os.path.abspath(servicemanager.file)
servicemanager.PrepareToHostSingle(FdbService)
servicemanager.Initialize('FdbService', evtsrc_dll)
servicemanager.StartServiceCtrlDispatcher()
except win32service.error as details:
if details[0] == winerror.ERROR_FAILED_SERVICE_CONTROLLER_CONNECT:
win32serviceutil.usage()
else:
win32serviceutil.HandleCommandLine(FdbService)

然后安装服务：
python FdbService.py install
python FdbService.py --startup auto install

此时系统服务项出现如下图片所示服务：

我的问题是，该服务的执行程序为什么是win32下的pythonservice.exe，而不是需要执行的脚本FdbService.py?

因为你的脚本FdbService.py不是可执行文件，需要把它打包成可执行文件：