怎么用python登录fofa？

import requests
from lxml import etree
import random
import time
import urllib
import base64

data='"TWCMS"'
headers={
'cookies':'fofa_taken=eyJhbGciOiJIUzUxMiIsImtpZCI6Ik5XWTVZakF4TVRkalltSTJNRFZsWXpRM05EWXdaakF3TURVMlkyWTNZemd3TUdRd1pUTmpZUT09IiwidHlwIjoiSldUIn0.eyJpZCI6MTU3MzA0LCJtaWQiOjEwMDA5MTk3MiwidXNlcm5hbWUiOiJkeWhhY2tlcnMiLCJleHAiOjE2NjIyMDM0NTN9.5xtBAtm6-wTzobg1ROoBAM25qzsYHYYXvGSkukPZrjmKU2Qwjyrzx9eCgXhP8rS_ZPK7WB_PVK5JCtlx2yTxDw'
}
url='https://fofa.info/result?qbase64=%27
newdata=str(base64.b64encode(data.encode("utf-8")), "utf-8")
urls=url+newdata
print(urls)
re=requests.get(urls,headers=headers).content
print(re.decode('utf-8'))

为什么登录不了？

xpath如下：

//span[@class="aSpan"]/a/@href

使用xpath表达式就行了，不存在失效的情况

//a[@target='_blank']/@href

img

不管是否有协议名，都可以匹配

  1. xpath 取得a标签

  2. url正则表达式

/^((ht|f)tps?)://[\w-]+(.[\w-]+)+([\w-.,@?^=%&:/+#]*[\w-@?^=%&/+#])?$/