PHP：json_encode将斜杠改为\ /

I have a variable which contains a path in json_encode /users/crazy_bash/online/test/

but json_encode converts the path to this:

 \/users\/crazy_bash\/online\/test\/

Why? How can i display a normal path?

the code

$pl2 = json_encode(array(
    'comment' => $nmp3,
    'file' => $pmp3
));
echo($pl2);

It's perfectly legal JSON, see http://json.org/. \/ is converted to / when unserializing the string. Why worry about it if the output is unserialized by a proper JSON parser?

If you insist on having \/ in your output, you can use str_replace():

// $data contains: {"url":"http:\/\/example.com\/"}
$data = str_replace("\\/", "/", $data);
echo $data; // {"url":"http://example.com/"}

Note that it's still valid JSON by the definition of a string:

_{(source: json.org)}

You'll have to decode it before usage.

json_decode()

Escaped solidus is legal. But if you want a result without escaping, use JSON_UNESCAPED_SLASHESin json_encode option. However, this was added after PHP 5.4. So, str_replace('\\/', '/', $pl2); would be helpful.

That's what json_encode is supposed to do. Once you json_decode or JSON.parse it, it's fine.

var f = {"a":"\/users\/crazy_bash\/online\/test\/"}
console.log(f.a); // "/users/crazy_bash/online/test/"

var h = JSON.parse('{"a":"\/users\/crazy_bash\/online\/test\/"}');
console.log(h.a); // "/users/crazy_bash/online/test/"

I had the same problem, basically you need to decode your data and then do the encode, so it works correctly without bars, check the code.

$getData = json_decode($getTable);                  
$json = json_encode($getData);

header('Content-Type: application/json');
print $json;