链表中读取字符失败了

首先感谢帮忙，我先上代码了
代码如下：
#include
#include

typedef struct linkedlist
{
int num;
char arr[20];
struct linkedlist* next;
}node;

node* NODE()
{
int Num;
node* head;
head = (node*)malloc(sizeof(node));
node* newNode;
node* now = head;

while (1) {
    int a;
    printf("数字：\n");
    scanf_s("%d", &Num);
    if (Num != 0) {
        //new = (node*)malloc(sizeof(node*));
        newNode = (node*)malloc(sizeof(node));
        printf("字符：\n");
        scanf_s("%s", &newNode->arr);
        newNode->num = Num;
        newNode->next = NULL;
        now->next = newNode;
        now = newNode;
    }
    else goto a;
}

a:
return head;
}

void output(node* head) {
node* put = head->next;
while (put != NULL)
{
printf("%d\n", put->num);
put = put->next;
}
}

int main()
{
node* head = NULL;
head = NODE();
output(head);
}
错误如下：

但是要是我改成这样：
#include
#include
char gets(char* str);
typedef struct linkedlist
{
int num;
char arr[20];
struct linkedlist* next;
}node;

node* NODE()
{
int Num;
node* head;
head = (node*)malloc(sizeof(node))
node* newNode;
node* now = head;

while (1) {
    int a;
    printf("数字：\n");
    scanf_s("%d", &Num);
    if (Num != 0) {
        newNode = (node*)malloc(sizeof(node));
        printf("字符：\n");
        gets(newNode->arr);//我在这里改用为gets
        newNode->num = Num;
        newNode->next = NULL;
        now->next = newNode;
        now = newNode;
    }
    else goto a;
}

a:
return head;
}

void output(node* head) {
node* put = head->next;
while (put != NULL)
{
printf("%d\n", put->num);
put = put->next;
}
}

int main()
{
node* head = NULL;
head = NODE();
output(head);
}
它就会直接跳过gets ，我实在搞不懂是为啥了

感觉链表好难学，老是出错啊！

scanf_s("%s", &newNode->arr);
改为
scanf_s("%s", &newNode->arr,20);
=======
gets不能连续读两行，中间要价格getchar()接收到换行符。