var list = ["a", "b", "c", "d", ] , routers = [];
var asyncRoutes = [
{ name: "a",
children: [
{ name: "b", }, { name: "c", }, { name: "d",}, { name: "e", },{ name: "f", },
],
},
];
如何遍历出来
asyncRoutes = [ { name: "a",children: [ { name: "b", }, { name: "c", }, { name: "d",} ], },] 这样的格式呢?
我是这样的写法,不能得到 children里面的数据
list.forEach((key) => {
routers.push(
...asyncRoutes.filter((item) => {
if (item.children && item.children.length > 1) {
item.children = item.children.filter((i) => {
return i.name == key;
});
}
return item.name === key;
})
);
});
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script>
var list = ["a", "b", "c", "d",], routers = [];
var asyncRoutes = [
{
name: "a",
children: [
{ name: "b", }, { name: "c", }, { name: "d", }, { name: "e", }, { name: "f", },
],
},
];
var obj = {};
obj.children = [];
var data = list.forEach((item, index) => {
if (index == 0) {
obj.name = item;
return
}
var child_obj = {
children: item
}
obj.children.push(child_obj);
});
routers.push(obj)
console.log(routers);
</script>
</body>
</html>
在写个方法,递归