查询没有学全所有课程的学号姓名代码如下--表的联结select s2.学号,s1.姓名from chengji as s2 LEFT JOIN student as s1on s1.学号=s2.学号GROUP BY s2.学号having COUNT(DISTINCT 课程号)<(select count(DISTINCT 课程号) from subject);表如下
group by 学号,姓名 这样就可以了