先是报错Run-Time Check Failure #2 - Stack around the variable 'arr' was corrupted.修改之后可以正常运行但是不能实现目标
NEW:
//建立数组和变量num2
int num2 = 0;
int arr[8] = { 6, 3, 4, 5, 1, 8, 7, 2 };
//打印未修改的arr
for (int i = 0; i <= 7; i++) {
cout << arr[i];
}
//替换数字,使数组内数字从大到小排序
for (int num1 = 0; num1 < 8; num1++) {
num2 = num1 + 1;
int temp;
if(arr[num1] > arr[num2]) {
temp = arr[num1];
arr[num1] = arr[num2];
arr[num2] = temp;
}
}
//打印修改后的arr
cout << "\n";
for (int i = 0; i <= 7; i++) {
cout << arr[i];
}
63451872
34516728请按任意键继续
基本都在程序里了,第一遍尝试没用变量,就直接用的数字,运行没有问题,把数字替代成变量之后前三个数字没有问题,后面仍不规律
数组按照从大到小顺序排列
for (int num1 = 0; num1 < 8; num1++) {
num1<8改为num1<7
否则当num1=7时,num2就等于8,数组越界访问了
再说冒泡是双循环,你这只是单循环啊
for (int num1 = 0; num1 < 7; num1++)
{
for(int num2=0;num2<7-num1;num2++)
{
if(arr[num2] > arr[num2+1])
{
int t = arr[num2];
arr[num2] = arr[num2+1];
arr[num2+1] = t;
}
}
}
1.冒泡排序需要双重for循环,你这只循环一次怎么改也不对
2.外层循环要从0到n-1,内层循环从1到n
<8要改为<7才对,否则直接越界了
int arr[8] = { 6, 3, 4, 5, 1, 8, 7, 2 };