php7.1 连接sqlserver2008r2 如何测试成功

用php7.1 连接sqlserver2008r2 如何测试成功并做简单查询,代码怎么写。

举例
$host = '11.11.11.6,3000';
$user = 'abc';
$password = '123456';
$dbname = 'kk';

表里面有两个字段 一个是a 一个是b 就是根据a查询出a=1对应的b内容


<?phpheader("Content-type: text/html; charset=utf-8");
 $serverName = "192.168.0.1"; //数据库服务器地址 
$uid = "site_user"; //数据库用户名 
$pwd = "zkJ1246g"; //数据库密码 
$connectionInfo = array("UID"=>$uid, "PWD"=>$pwd, "Database"=>"db_site");
 $conn = sqlsrv_connect( $serverName, $connectionInfo); 
if( $conn == false) { 
echo "连接失败!"; die( print_r( sqlsrv_errors(), true));
 }else{ 
echo "连接成功!"; 
} 
$query = sqlsrv_query($conn, "select * from 数据库表"); 
while($row = sqlsrv_fetch_array($query)) { 
 print_r($row); 
}?>

https://blog.csdn.net/chimo_1/article/details/78378426?utm_medium=distribute.pc_relevant.none-task-blog-2~default~baidujs_title~default-4-78378426-blog-116023378.pc_relevant_multi_platform_whitelistv1&spm=1001.2101.3001.4242.3&utm_relevant_index=7