不存在从“”到“*”的适当转换函数，如何解决？

不存在从“”到“*”的适当转换函数

#include<iostream>
using namespace std;
#include<string>
struct student {
    string name;
    int score;


};

struct teacher {
    string name;
    struct student stu[5];


};
void swaper(teacher tea[], int len) {
    string name[] = { "wang","li","zhao","xiaowang","xiaoli","xiaoming","xiaozhang","xiaogou" };
    for (int i = 0; i < len; i++) {
        tea[i].name = name[i];
        cout << "teacher's name:" << tea[i].name << endl;

        for (int j = 0; j < 5; j++) {
            tea[i].stu[j].name = name[j + 3];
            
            tea[i].stu[j].score = rand() % 61 + 40;
            cout << "student'name:" << tea[i].stu[j].name << "student'score:" << tea[i].stu[j].score << endl;

        }

    }

}



int main() {
    teacher tea[3];
    int len=sizeof(tea)/sizeof(tea[0]);
    swaper(tea[3], len);
    



}

40行去掉[3]

加上rand函数的头文件<stdlib.h>，以及把main函数的调用swaper函数的参数的tea[3]改为tea后（swaper函数第一个参数是teacher指针，所以传入tea），发现正常运行，修改如下：

#include<iostream>
#include <stdlib.h> 
using namespace std;
#include<string>
struct student {
    string name;
    int score;
 
 
};
 
struct teacher {
    string name;
    struct student stu[5];
 
 
};
void swaper(teacher tea[], int len) {
    string name[] = { "wang","li","zhao","xiaowang","xiaoli","xiaoming","xiaozhang","xiaogou" };
    for (int i = 0; i < len; i++) {
        tea[i].name = name[i];
        cout << "teacher's name:" << tea[i].name << endl;
 
        for (int j = 0; j < 5; j++) {
            tea[i].stu[j].name = name[j + 3];
            
            tea[i].stu[j].score = rand() % 61 + 40;
            cout << "student'name:" << tea[i].stu[j].name << " , student'score:" << tea[i].stu[j].score << endl;
 
        }
 
    }
 
}
 
 
 
int main() {
    teacher tea[3];
    int len=sizeof(tea)/sizeof(tea[0]);
    swaper(tea, len);
    
 
 
 
}
 

错误信息里面都会指明是哪一行的