python super( )method疑问

疑问在这段代码的注释里


class Dog:
    kennel = 0
    def __init__(self, breed):
        self.breed = breed
        Dog.kennel += 1
    def __str__(self):
        return self.breed + " says: Woof!"


class SheepDog(Dog):
    def __str__(self):
        return super().__str__() + " Don't run away, Little Lamb!"
class LowlandDog(SheepDog):
    def __str__(self):
        return Dog.__str__(self) + " I don't like mountains!"#这里用到Dog class的时候为什么要加self,其他像super().__str__()这种就不用加?
class GuardDog(Dog):
    def __str__(self):
        return super().__str__() + " Stay where you are, Mister Intruder!"


rocky = LowlandDog("Collie")
luna = GuardDog("Dobermann")
print(rocky.kennel)                           #这里的ouput是2,但我觉得是1,有点不太明白?
print(rocky)

因为super()里隐式传了self,类方法里就不用再传了
kennel是Dog类属性,并不属于某个实例,任何一个实例都可以修改和访问。所以当实例rocky的时候,kennel变成1,再实例luna的时候,kennel就变成了2。

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