Python找矩阵最小的值

输入：5×5的矩阵，数字用空格隔开
输出：矩阵中最小的值所在的行，列，和这个值
有人会嘛
ballball求解

nums=[]
for i in range(5):
    nums += list(map(int,input().split()))
minnum=min(nums)
x=nums.index(minnum)
row = x//5
col = x-5*row
print(row,col,minnum)

ls = []

for i in range(5):
    a = input().split()
    a = list(map(lambda x: int(x),a))
    ls.append(a)

row = 0
col = 0
for i in range(0,len(ls)):
    for j in range(0,len(ls[i])):
        if ls[row][col] > ls[i][j]:
            row = i
            col = j
print(row,col,ls[row][col])