#有如下列表
A = [{"id": 1, "city": "北京"}, {"id": 2, "city": "上海"}, {"id": 3, "city":"广州"}, {"id": 4, "city": "北京"}]
# 根据 city中重复的值 返回id
city=[i['city'] for i in A]
count={i:city.count(i) for i in city}
res={}
for i,j in count.items():
if j>1:
temp=[k['id'] for k in A if k['city']==i]
res[i]=temp
print(res)
输出:
{'北京': [1, 4]}