C语言写万年历，我实在写不出来了
适用于从公元1年1月1日到公元10000年之间所有日期的显示。
1.提供系统操作的主界面；
2.查询某年某月某日（阳历）是星期几；
3.判断某年是否是闰年；
4.查询某月的最大天数；
5.打印某年的全年日历或某年某月的月历。
用visual系统编写
回答的好了可以追加酬劳的
实在是写不出来了各位教教我怎么写吧！！
#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,h,k,r,m,n,s,year,mon[12]={31,28,31,30,31,30,31,31,30,31,30,31},day[12];
printf("请输入年份：");
scanf("%d",&year);
printf("想要排几行：");
scanf("%d",&n);
if(year%4==0&&year%100!=0||year%400==0)
mon[1]=29;
day[0]=(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;
for (m=1;m<12;m++)
day[m]=(day[m-1]+mon[m-1])%7;
for (i=1;i<=n;i++)
{
printf("_____________________ ");
}
printf("\n");
for(i=1;i<=12/n+1;i++)
{
for(j=1;j<=10;j++)
{
for (r=1,s=(i-1)*n;r<=n&&s<12;r++,s++)
{
if (j==1)
printf("%8d年%3d月 ",year,s+1);
if (j==2||j==10)
printf("_____________________");
if (j==3)
printf(" 日 一 二 三 四 五 六");
for (k=(j-4)*7+1,h=1;k<=42&&h<=7;k++,h++)
{
if (k<=mon[s]+day[s])
{
if (j==4)
{
if (k<=day[s])
printf(" ");
else
printf("%3d",k-day[s]);
}
else if (j!=1&&j!=2&&j!=3&&j!=10)
printf("%3d",k-day[s]);
}
else
printf(" ");
}
printf(" ");
}
printf("\n");
}
}
system("color B0");
system("pause");
return 0;
}
显示某年全年日历的运行结果（其它要求的功能都有，可以看截图中的菜单）：
代码：
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>
//没有考虑1582年10月缺失的10天
// 判断闰年
int isleapyear(int year)
{
if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
return 1;
else
return 0;
}
// 获取月份的天数
int daysofmonth(int year, int mon)
{
int arr[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
if (isleapyear(year))
arr[2] = 29;
return arr[mon];
}
//返回年的累加天数
int calMonth(int year, int month)
{
int shift = 0;
if (isleapyear(year))
shift = 1;
switch (month)
{
case 0:return 0;
case 1:return 31;
case 2:return 31 + 28 + shift;
case 3:return 31 + 28 + 31 + shift;
case 4:return 31 + 28 + 31 + 30 + shift;
case 5:return 31 + 28 + 31 + 30 + 31 + shift;
case 6:return 31 + 28 + 31 + 30 + 31 + 30 + shift;
case 7:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + shift;
case 8:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + shift;
case 9:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + shift;
case 10:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + shift;
case 11:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + shift;
case 12:return 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + shift;
default:return 0;
}
}
// 判断某天是周几
int weekofday(int year, int mon, int day)
{
// 1900-1-1 星期一
int days = 0;
if (year < 1900)
{
//1.计算从year+1到1900年的天数
for (int y = year + 1; y < 1900; y++)
{
if (isleapyear(y))
days += 366;
else
days += 365;
}
//2.year年的天数
if (isleapyear(year))
days += 366 - calMonth(year, mon - 1) - day;
else
days += 365 - calMonth(year, mon - 1) - day;
int wk = days % 7;
return (7 - wk);
}
else
{
//1.计算从1900年到year的天数
for (int y = 1900; y < year; y++)
{
if (isleapyear(y))
days += 366;
else
days += 365;
}
//2.year年的天数
days += calMonth(year, mon - 1) + day - 1;
int wk = days % 7 + 1;
return wk;
}
}
void showwk(int wk)
{
switch (wk)
{
case 1:
printf("星期一\n"); break;
case 2:
printf("星期二\n"); break;
case 3:
printf("星期三\n"); break;
case 4:
printf("星期四\n"); break;
case 5:
printf("星期五\n"); break;
case 6:
printf("星期六\n"); break;
case 7:
printf("星期日\n"); break;
}
}
//显示某年某月的日历
void showRl(int year, int mon)
{
int day, wk, days;
int i, j;
const char* weeks[] = { " ","一","二","三","四","五","六","日" };//仿windows日历显示
days = daysofmonth(year, mon);
for (i = 1; i <= 7; i++)
printf("%2s ", weeks[i]);
printf("\n");
for (day = 1; day <= days; day++)
{
wk = weekofday(year, mon, day);
if (day == 1)
{
for(j=1;j<wk;j++)
printf(" ");
}
if(wk != 7)
printf("%2d ", day);
else
printf("%2d\n", day);
}
printf("\n\n");
}
//显示某年的日历
void showYear(int year)
{
int i = 1;
for (; i <= 12; i++)
{
printf("%d年%d月日历：\n",year,i);
showRl(year, i);
}
}
int main()
{
int year, mon, day;
int op;
int wk;
while (1)
{
system("cls");
printf("***************************************\n");
printf(" 万年历 \n");
printf("1.查询某年某月某日星期几\n");
printf("2.判断某年是否是闰年\n");
printf("3.查询某月的最大天数\n");
printf("4.打印某年的全年日历\n");
printf("5.打印某年某月的日历\n");
printf("0.退出程序\n");
printf("***************************************\n");
printf("请选择：");
while (1) {
scanf("%d", &op);
if (op >= 0 && op <= 5)
break;
else
printf("请输入0-5的值：");
}
system("cls");
switch (op)
{
case 1:
printf("请输入日期（如2020 2 2）:");
scanf("%d %d %d", &year, &mon, &day);
wk = weekofday(year, mon, day);
showwk(wk);
break;
case 2:
printf("请输入年份：");
scanf("%d", &year);
if (isleapyear(year))
printf("%d年是闰年\n", year);
else
printf("%d年不是闰年\n", year);
break;
case 3:
printf("请输入年月：");
scanf("%d %d", &year, &mon);
printf("%d年%d月的最大天数是%d\n", year, mon, daysofmonth(year, mon));
break;
case 4:
printf("请输入年：");
scanf("%d", &year);
showYear(year);
break;
case 5:
printf("请输入年月：");
scanf("%d %d", &year, &mon);
printf("%d年%d月日历如下：\n",year,mon);
printf("---------------------------------\n\n");
showRl(year,mon);
break;
case 0:
return 0;
}
system("pause");
}
return 0;
}
供参考：
#include <iostream>
#include <iomanip>
#include <string>
#include <windows.h>
using namespace std;
string week[7]={"星期一","星期二","星期三","星期四","星期五","星期六","星期日"};
int isLeap(int y) // 闰年判断函数
{
if((y%4==0 && y%100!=0)||(y%400==0))
return 1;
else
return 0;
}
int GetDaysOfMonth(int y, int m)//每月的天数
{
int daysOfMonth[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
if(isLeap(y) && m == 2) return daysOfMonth[m-1]+1;
return daysOfMonth[m-1];
}
int Get_Week(int y,int m,int d)//计算星期数（星期一 -- 星期日：0 -- 6）
{
int week = -1;
if(m==1 || m == 2){
m += 12; y--;
}
week=(d+2*m+3*(m+1)/5+y+y/4-y/100+y/400)%7;
return week;
}
int GetDaysOfYear(int y,int m,int d)//某天是该年的第几天
{
int i,days=0;
for (i=1;i < m;i++)
days += GetDaysOfMonth(y,i);
days += d;
return days;
}
void ShowCalendar(int year,int month,int day=1)//格式输出日历表
{
int i,k,count=0;//每月天数
int dayofweek=0;//星期几
cout<<setw(12)<<" "<<year<<"年"<<month<<"月"<<endl;
cout<<"--------------------------------------\r\n";
cout<<" 日 一 二 三 四 五 六 \r\n";
cout<<"--------------------------------------\r\n";
dayofweek=(1+Get_Week(year,month,day))%7;//每月1日星期数
count=GetDaysOfMonth(year,month); //每月天数
for(i=0;i<dayofweek;i++) cout<<setw(5)<<" ";//填充前面空格
for(i=1,k=dayofweek;i<=count;i++,k++){
cout<<setw(5)<<i;
if((k+1)%7==0 && i!=count) cout<<endl;//满7天，换行
}
cout<<"\r\n--------------------------------------\r\n\r\n";
}
void menu() //菜单函数
{
cout<<"\t\t\t\t\t----------------------------------"<<endl;
cout<<"\t\t\t\t\t* *"<<endl;
cout<<"\t\t\t\t\t* 欢迎使用本系统 *"<<endl;
cout<<"\t\t\t\t\t* *"<<endl;
cout<<"\t\t\t\t\t----------------------------------"<<endl;
cout<<endl;
cout<<endl;
cout<<"\t\t\t本系统具有以下功能"<<endl;
cout<<"\t\t\t\t\t1.打印某年的全年日历"<<endl;
cout<<"\t\t\t\t\t2.打印某年某月的月历"<<endl;
cout<<"\t\t\t\t\t3.查询某年某月某日是星期几"<<endl;
cout<<"\t\t\t\t\t4.判断某年某月某日是本年度第几天"<<endl;
cout<<"\t\t\t\t\t5.判断某年是否闰年"<<endl;
cout<<"\t\t\t\t\t6.查询某年某月的最大天数"<<endl;
cout<<"\t\t\t\t\t7.退出"<<endl;
cout<<"\t\t\t请选择按键(1-7):";
}
int main()
{
int year=0,month=0,day=0,nChoise=1;
while (nChoise){
menu();
cin>>nChoise;
switch (nChoise)
{
case 1:
cout<<"输入年份："; cin>>year;
for (month=1;month<=12;month++)
ShowCalendar(year,month,1);
break;
case 2:
cout<<"输入年份："; cin>>year;
cout<<"输入此年月份(1-12)："; cin>>month;
ShowCalendar(year,month,1);
break;
case 3:
cout<<"输入年份："; cin>>year;
cout<<endl<<"输入月份(1-12)："; cin>>month;
cout<<endl<<"输入此年此月相应的日期(1-28:29:30:31)："; cin>>day;
cout<<endl<<"该天是:"<<week[Get_Week(year,month,day)]<<endl;
break;
case 4:
cout<<"输入年份："; cin>>year;
cout<<endl<<"输入月份(1-12)："; cin>>month;
cout<<endl<<"输入此年此月相应的日期(1-28:29:30:31)："; cin>>day;
cout<<endl<<"该天是该年度第"<<GetDaysOfYear(year,month,day)<<"天。"<<endl;
break;
case 5:
cout<<"输入年份："; cin>>year;
if(isLeap(year)) cout<<"该年是闰年。"<<endl;
else cout<<"该年非闰年。"<<endl;
break;
case 6:
cout<<"输入年份："; cin>>year;
cout<<"输入此年月份(1-12)："; cin>>month;
cout<<"该月最大天数:"<<GetDaysOfMonth(year, month)<<endl;
break;
case 7:
nChoise = 0;
break;
default:
nChoise = 1;
cout<<"无效的菜单项！"<<endl;
break;
}
system("pause");
system("cls");
}
return 0;
}
进行到哪一步了
好大一个工程，可参https://blog.csdn.net/xianfajushi/article/details/103925143