按照题目提示的要求,是先通过比较a in b得到True或False,然后再用True=1,False=0这样的默认转换,去读取yes或no
res = ['NO','YES'] a = input() b = input() print(res[a in b])
a1 = input('') a2 = input('') if a1 in a2: print('YSE') else: print("No")