计算1!+..+n!的值。函数或函数调用必须"def f(i):ifi==0:sum=1else:sum=i*f(i-1)return sumn=eval(input("input n(n>=2):print(f(n))
这样写。
n = int(input()) jie = 1 sum = 0 i = 1 while n >= i: jie = jie * i sum = sum + jie i = i + 1 print(sum)