c51单片机的计数问题

c51单片机
c语言设计:上电后数码管从0000开始按每秒计数直到9999,按键1按下时从当前计数值开始每秒减1计数,再按按键1时恢复增计数,按键2按下时停止计数,再按按键2时继续计数
下面是我画好的原理图。自己写的代码不能运行。希望可以帮帮忙。谢谢!

img


#include "REG52.h"
unsigned char code smgduan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0,64}; //共阴0~F消隐减号
unsigned char Js=0, miao=0;//中断计时 秒 分 时 毫秒
sbit k0=P3^2;
sbit k1=P3^3;
void smxs(unsigned char mz, unsigned char w)
{
    unsigned char Xd=0;
    P1=255;
    P1=255-smgduan[mz];
    P0=w;
    while(++Xd);
}
void ZhongDuanSheZhi()
{
    TH0+=(65536-9216*5)/256;/*定时器赋初值,定时50ms触发中断,自动补偿方式*/
    TL0+=(65536-9216*5)%256; 
    TMOD=0X01;//16位定时器/计数器
    TR0=1; //启动定时器T0。
    ET0=1; //开启定时器
    EA=1; //全局中断开关
}
void main()
{
    unsigned char Xd=0,k=1;//消抖
    unsigned int shu=0;
    ZhongDuanSheZhi();
    while(1)
    {
        if(k0==0&&++Xd==0){k=!k;Js=0;while(k0==0);}
        if(k1==0&&++Xd==0){TR0=!TR0;Js=0;while(k1==0);}
        smxs(shu/1000,16);smxs(shu/100%10,32);smxs(shu/10%10,64);smxs(shu%10,128);
        if(Js==20)
        {
            Js=0;
            if(shu<10000)if(k)++shu;else --shu;
        }
    }
}
void ZhongDuan() interrupt 1
{
    ++Js;
    TH0+=0X4c;
    TL0+=0X00;        
}

实际制作时,应采用共阳数码管,PNP三极管驱动“位”,还要有限流电阻。


 
#include "reg52.h"
typedef unsigned char u8;
typedef unsigned int u16;
#define smg P0
sbit button_1=P3^0;
sbit button_2=P3^1;
u16 k = 0;
u16 smgduan[10] = {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
 
void delay(u16 i)
{
    while(i--);
}
void keypros()
{
    if (button_1 == 0)
    {
        delay(500);
        if (button_1 == 0)
        {
            if (k>=9999)
            {
                k=0;
            }
            else
            {
                k = k + 1;
            }
        }
        while(!button_1);   
    }
    if (button_2 == 0)
    {
        delay(500);
        if (button_2 == 0)
        {
            if (k<=0)
            {
                k=9999;
            }
            else
            {
                k = k-1;
            }
        }
        while(!button_2);
    }
}
void main()
{
    int q,b,s,g;
    while(1)
    {
        keypros();
        q = k/1000;
        b = k%1000/100;
        s = k%100/10;
        g = k%10;
        delay(100);
 
        P2 = 0x07;
        smg = ~smgduan[q];
        delay(5);
 
        P2 = 0x0e;
        smg = ~smgduan[b];
        delay(5);
 
        P2 = 0x0d;
        smg = ~smgduan[s];
        delay(5);
 
        P2 = 0x0b;
        smg = ~smgduan[g];
        delay(5);
 
    }
}