编程输出用电量最多和最少的月份以及对应的用电量

某企业一年的用电情况存储在字典中：{"一月":43428,"二月":48467,"三月":57333,"四月":61440,"五月":65000,"六月":75000,"七月":78110,"八月":88888,"九月":78050,"十月":68000,"十一月":71122,"十二月":55006}，编程输出用电量最多和最少的月份以及对应的用电量，输出全年总用电量及平均每月用电量。

填入合适代码，使程序完整。

dct={"一月":43428,"二月":48467,"三月":57333,"四月":61440,"五月":65000, \

 "六月":75000,"七月":88888,"八月":88888,"九月":78110,"十月":68000, \

 "十一月":71122,"十二月":55006}

for key,value in ① :

if value==   ②  :

    print("用电量最多月份是{}，用电量{}".format(key,value))

if value==   ③  :

    print("用电量最少月份是{}，用电量{}".format(key,value))

s= ④

print("全年用电量{}，平均每月用电量{}".format(s,s/12))

前面回答的问题，请采纳，谢谢

dct={"一月":43428,"二月":48467,"三月":57333,"四月":61440,"五月":65000, \

 "六月":75000,"七月":88888,"八月":88888,"九月":78110,"十月":68000, \
 
 "十一月":71122,"十二月":55006}
for key,value in dct.items() :

    if value==   max(dct.values())  :
    
        print("用电量最多月份是{}，用电量{}".format(key,value))
    
    if value==   min(dct.values())  :
    
        print("用电量最少月份是{}，用电量{}".format(key,value))
s= sum(dct.values())

print("全年用电量{}，平均每月用电量{}".format(s,s/12))