<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script>
let arr = [9980, 998, 499, 198, 99, 50, 30, 20, 10];
let arr1 = [1, 1, 5, 7, 13, 5, 15, 13, 11, 46];
let result = [];
let combination = []
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr1.length; j++) {
combination.push({
arr: arr[i],
arr1: arr1[j],
value: arr[i] * arr1[j] - 9980
})
}
}
let minvalue = Math.min.apply(null, combination.map(item => Math.abs(item.value)))
result = combination.filter(item => Math.abs(item.value) == minvalue)
console.log(combination, result, '===')
</script>
</body>
</html>
其实你把couponTypes讲成单价,couponsNums讲成数量,这样更好理解一点
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>Document</title>
</head>
<body>
<script>
let couponTypes = [9980, 998, 499, 198, 99, 50, 30, 20, 10];
let couponsNums = [1, 1, 5, 7, 13, 5, 15, 13, 11, 46];
function getArr(couponTypes, couponsNums, value) {
let result = [];
for (let i = 0; i < couponTypes.length; i++) {
for (let j = 0; j < couponsNums.length; j++) {
if (couponTypes[i] * couponsNums[j] === value) {
result.push({
couponTypes: couponTypes[i],
couponsNums: couponsNums[j],
value: value,
});
}
}
}
return result;
}
console.log("getArr", getArr(couponTypes, couponsNums, 9980));
</script>
</body>
</html>
没太理解什么意思
可以是重复的使用吧