如何将十个字符串连在一起啊

#include<stdio.h>
int main()
{
    char s1[10], s2[10], s3[10], s4[10], s5[10], s6[10], s7[10], s8[10], s9[10], s10[10];
    scanf("%s", &s1);
    scanf("%s", &s2);
    scanf("%s", &s3);
    scanf("%s", &s4);
    scanf("%s", &s5);
    scanf("%s", &s6);
    scanf("%s", &s7);
    scanf("%s", &s8);
    scanf("%s", &s9);
    scanf("%s", &s10);
    int i = 0;
    int j = 0;
    char *str;
    char a[100];  
    str = &s1[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }
    str = &s2[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }
    str = &s3[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s4[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s5[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s6[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s7[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s8[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s9[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    str = &s10[0];
    while(*str != '\0')
    {
        a[i] = *str;
        i++;
        str++;
    }    
    a[i] = '\0';   
    printf("%s\n", a);  
    return 0;
}

在windows平台下，通常会这么干：
wsprintf(buffer,"%s%s%s%s%s%s%s%s%s%s",str1,str2,str3,str4,str5,str6,str7,str8,str9,str10);
其他平台的话，我记得string.h里面有个专门拼接字符串的函数，具体名字不记得了，有兴趣的可以查一下。

添加#include<string.h>，使用strcat函数可以拼接两字符串，如：strcat(s1,s2)将s2拼接到s1后面，s1="ab"，s2="cd"，拼接后，s1=“abcd”

用二维数组，可以减少代码量：

#include<stdio.h>
int main()
{
    int i=0,j;
    char *str,ss[10][10],a[100]; 
    
    for(j=0;j<10;j++)
    {
        scanf("%s", &ss[j]);
    }
 
    for(j=0;j<10;j++)
    {
        str = &ss[j][0];
        while(*str != '\0')
        {
            a[i] = *str;
            i++;
            str++;
        }
    }
    a[i] = '\0';   
    printf("%s\n", a);  
    return 0;
}