将数据从大到小分成五档，分别记为12345

数据如下
0.266
0.062
0.038
0.048
0.015
0.078
0.104
0.353
0.054
0.084

import more_itertools as mi

s = [0.266,0.062,0.038,0.048,0.015,0.078,0.104,0.353,0.054,0.084]
s.sort()
resu = list(map(list, mi.divide(5, s)))
print(resu)

lis=[0.266,0.062,0.038,0.048,0.015,0.078,0.104,0.353,0.054,0.084]
Lis=[sorted(lis,reverse=True)[i:i+2] for i in range(0,len(lis),2)]
k_v={}
n=1
for i in Lis:
    if n<6:
        k_v[n]=i
    else:
        break
    n+=1
print(k_v)