统计单词个数Python

统计单词个数
【问题描述】从键盘输入英文句子，统计每个单词出现的次数。【样例输入】to be or not to be
【样例输出】to:2
be:2
or:1
not:1

s = input()
dic = {}
for i in s.split():
    dic[i] = dic.get(i,0)+1
for s,n in dic.items():
    print(f'{s}:{n}')

'''--result:
In: 'to be or not to be'
Out:
to:2
be:2
or:1
not:1
'''

import collections

a="to be or not to be"
lis=[i for i in a.split(" ")]
b=collections.Counter(lis)

print(b)

s = input(">>>")

d = {}
for i in s.split():
    d[i] = d.get(i, 0) + 1
    
for i, j in sorted(d.items(), key = lambda x: x[1], reverse = True):
    print(f"{i}:{j}")

def calcnt(inputstr: str):
    sl = inputstr.split(' ')
    dic: dict = {}
    cnt = 0
    for i in sl:
        if dic.get(i) is not None:
            dic[i] += 1
        else:
            cnt += 1
            dic[i] = cnt
            cnt = 0

    for key, val in dic.items():
        print(key, ":", val, "\n")

if __name__ == '__main__':
    calcnt(input("输入英文句子，空格分开："))

sentence = input("请输入需要统计的英文句子:")
for ch in ",.?!":
   sentence=sentence.replace(ch, " ")

words=sentence.split()
dicts={}
for word in words:
   if word in dicts:
       dicts[word] += 1
   else:
       dicts[word]=1
items=list(dicts.items())
items.sort(key=lambda x: x[1], reverse=True)
for item in items:
   word, count=item
   print("{:<12}{:>5}".format(word, count))