C语言如何把该16进制字符转换为ip地址？

我需要把第二个红框内容转换为IP地址，都是string类型，末尾的3B代表着;
能否给予代码参考？感谢

#include <stdio.h>
#include <string.h>

/* "AB" -> 0xAB */
int char_to_byte(const char *str_char, unsigned char *str_byte)
{
    unsigned char byte_high = 0x00;
    unsigned char byte_low = 0x00;
    byte_high = *str_char;
    byte_low = *(str_char + 1);

    if ((str_char == NULL) || (str_byte == NULL))
        return -1;

    /* byte High */
    if ((byte_high >= '0') && (byte_high <= '9'))
    {
        byte_high = byte_high - '0';
    }
    else if ((byte_high >= 'a') && (byte_high <= 'f'))
    {
        byte_high = byte_high - 'a' + 0x0a;
    }
    else if ((byte_high >= 'A') && (byte_high <= 'F'))
    {
        byte_high = byte_high - 'A' + 0x0a;
    }
    else
    {
        return -1;
    }

    /* byte Low */
    if ((byte_low >= '0') && (byte_low <= '9'))
    {
        byte_low = byte_low - '0';
    }
    else if ((byte_low >= 'a') && (byte_low <= 'f'))
    {
        byte_low = byte_low - 'a' + 0x0a;
    }
    else if ((byte_low >= 'A') && (byte_low <= 'F'))
    {
        byte_low = byte_low - 'A' + 0x0a;
    }
    else
    {
        return -1;
    }

    *str_byte = (byte_high << 4) + byte_low;
    return 0;
}

/* "ABCD..." -> [0xAB, 0xCD, ...] */
int hex_str_convert(const char *str_in, char *str_out)
{
    int i = 0;
    unsigned char tmp = 0;
    size_t len = strlen(str_in);

    for (i = 0; i < len / 2; i++)
    {
        if (char_to_byte(&str_in[i * 2], &tmp) == 0x00)
            *(str_out + i) = tmp;
        else
            return -1;
    }

    return 0;
}

int main()
{
    char str_out[64] = { 0 };
    const char *str_in = "3131372E37342E3133362E33343B";

    hex_str_convert(str_in, str_out);
    printf(str_out);

    return 0;
}

• 运行输出: 117.74.136.34;

#include <stdio.h>
#include <string.h>
char conv_to_upper_case(char ch)
{
    if(ch >= 'a' && ch <= 'z')
    { return (ch - 32); }
    else
    { return ch; }
}

char ascii_to_hex_nib(char ch)

{
    ch = conv_to_upper_case(ch);

    if(('0' <= ch) && (ch <= '9')) {
        return (ch - '0');
    }
    else if(('A' <= ch) && (ch <= 'F')) {
        return (ch - 'A' + 10);
    }
    else {
        return 0xff;
    }
}

void convert(char *str_in, char *str_out)
{
    int i;
    int len = strlen(str_in);
    //如果不想要最后的分号，把上面的值 - 2
    char tmp;
    for(i = 0; i< len/2; i++)
    {
        tmp = ascii_to_hex_nib(*(str_in + i * 2));
        tmp <<= 4;
        tmp |= ascii_to_hex_nib(*(str_in + i * 2 + 1));
        *(str_out + i) = tmp;
    }
    *(str_out + len/2) = 0;//end of string
}

int main()
{
    char str_in[] = {"3131372E37342E3133362E33343B"} ;
    char str_out[100];
    convert(str_in, str_out);
    puts(str_out);
    return 0;
}

#include <stdio.h>
int main()
{
    char t[]=
    {
        "3131372E37342E3133362E33343B\0"
    };
    int p=0,count=0;
    int ascll[150]={
        0
    };
    while(t[p]!='\0')
    {
        int a,b;
        if(t[p]<='Z'&&t[p]>='A')
        {
            a=(t[p]-'A'+10)*16;
        }
        else
        {
            a=(t[p]-48)*16;
        }
        if(t[p+1]<='Z'&&t[p+1]>='A')
        {
            b=(t[p+1]-'A'+10);
        }
        else
        {
            b=(t[p+1]-48);
        }
        ascll[count++]=a+b;
        p+=2;
    }
    printf("\n");
    for(int i=0;i<count-1;i++)
    {
        printf("%c",ascll[i]);
    }
    printf("\n");
    return 0;
}

是这样吗

#include <cstring>
#include <cstdio>
using namespace std;

int CharToInt(char c)
{
    if(c <= '9') return int(c-'0');
    else return int(c-'A'+10);
}

char a[1005];
int main()
{
    scanf("%s", a);
    int len = strlen(a);
    int i=0;
    while(i < len) printf("%c", CharToInt(a[i++]) * 16 + CharToInt(a[i++]));
}

#include <stdio.h>
#include <string.h>
 
//0xc0a82c05 转 192.168.44.5
 
int intToString(int num , char *buf ,int count)
{
    int a = num/100;
    int b = (num/10)%10;
    int c = num%10;
    if( a == 0)
    {
        if( b != 0)
        {
            buf[count++] = b + '0';
            buf[count++] = c + '0';
        }
        else
        {
            buf[count++] = c + '0';
        }
    }
    else
    {
        buf[count++] = a + '0';
        buf[count++] = b + '0';
        buf[count++] = c + '0';
    }
    return count;
}
char *intToChar(unsigned int number)
{
    static char buf[20] = {0};
    int count = 0;
    int idx = 24;
    while( idx >= 0 )
    {
        int num = (number>>idx) & 0xff;
        count = intToString(num , buf , count);
        if( idx != 0)
        {
            buf[count++] = '.';
        }
        idx -= 8;
    }
    return buf;
}
int main()
{
    int number = 0xc0a82c05;
    char *ret = intToChar( number );
    printf("ret = %s \n", ret);
    return 0;
}

#include<stdlib.h>
#include<stdio.h>
#include<ctype.h>
#include<string.h>
#include<assert.h>
int hex_char_to_dec(char hex_ch)
{
    if (isdigit(hex_ch))return hex_ch - '0';
    if ('A' <= hex_ch && hex_ch <= 'F')return 10 + hex_ch - 'A';
    assert(0);
    return 0;
}

void convert(const char* str, char ip[16])
{
    memset(ip, 0, sizeof(ip));
    int l = strlen(str);
    int addr_len = 0;
    for (int i = 0; i < l-1; i += 2)
    {
        char ch = hex_char_to_dec(str[i]) * 16 + hex_char_to_dec(str[i+1]);
        ip[addr_len++] = ch;
    }
}

int main()
{
    const char* hex_str = "3131372E37342E3133362E33343B";
    char ip[16] = { 0 };
    convert(hex_str, ip);
    printf("16进制字符串：%s\n", hex_str);
    printf("ip地址：%s\n", ip);
    return 0;
}