list1: [{
"letter": "A",
"cityName": "安吉",
"cityCode": "ANJ",
}, {
"letter": "B",
"cityName": "北京",
"cityCode": "PEK",
}, {
"letter": "C",
"cityName": "崇州",
"cityCode": "chongzhou",
},],
list2: {
'A': {
list: [{
"letter": "A",
"cityName": "安吉",
"cityCode": "ANJ",
},]
},
'B': {
list: [{
"letter": "B",
"cityName": "北京",
"cityCode": "PEK",
},]
},
'C': {
list: [{
"letter": "C",
"cityName": "崇州",
"cityCode": "chongzhou",
},]
},
}
let list1 = [
{
letter: "A",
cityName: "安吉",
cityCode: "ANJ",
},
{
letter: "B",
cityName: "北京",
cityCode: "PEK",
},
{
letter: "C",
cityName: "崇州",
cityCode: "chongzhou",
},
];
let list2 = {};
list1.forEach(function (item) {
list2[item.letter] = {
list: [item],
};
});
console.log("list2", list2);
1.用forEach()遍历list1,拿到每一个list1里的数据item
2.声明一个空的对象,对遍历后的每一项对行处理,然后放到空对象中