这个在平台上为什么提交不了（C语言合法标识符）

#include <stdio.h>

int main() {
    int n, i;
    char a[52];
    scanf("%d", &n);
    getchar();
    while (n--) {
        gets(a);
        if (a[0] == '_' || a[0] >= 'a' && a[0] <= 'z' || 'A' <= a[0] && a[0] <= 'Z') {
            for (i = 1; a[i] != '\0'; i++) {
                if (a[i] == '_' || a[i] >= 'a' && a[i] <= 'z' || a[i] >= '0' && a[i] <= '9' || 'A' <= a[0] && a[0] <= 'Z')
                    continue;
                else {
                    printf("no\n");
                    break;
                }
            }
            if (a[i] == '\0')
                printf("yes\n");
        } else
            printf("no\n");
    }
    return 0;
}

这样写没有发现有错误的样例啊，但为什么平台上就是过不了，是哪里出错了？

for中的if是
是'A' <= a[i] && a[i] <= 'Z' ,不是'A' <= a[0] && a[0] <= 'Z'

 if (a[i] == '_' || a[i] >= 'a' && a[i] <= 'z' || a[i] >= '0' && a[i] <= '9' || 'A' <= a[0] && a[0] <= 'Z')
            

改成

 if (a[i] == '_' || a[i] >= 'a' && a[i] <= 'z' || a[i] >= '0' && a[i] <= '9' || 'A' <= a[i] && a[i] <= 'Z')
            

你题目的解答代码如下：

#include <stdio.h>

int main() {
    int n, i;
    char a[52];
    scanf("%d", &n);
    getchar();
    while (n--) {
        gets(a);
        if (a[0] == '_' || a[0] >= 'a' && a[0] <= 'z' || 'A' <= a[0] && a[0] <= 'Z') {
            for (i = 1; a[i] != '\0'; i++) {
                //是'A' <= a[i] && a[i] <= 'Z'
                if (a[i] == '_' || a[i] >= 'a' && a[i] <= 'z' || a[i] >= '0' && a[i] <= '9' || 'A' <= a[i] && a[i] <= 'Z')
                    continue;
                else {
                    printf("no\n");
                    break;
                }
            }
            if (a[i] == '\0')
                printf("yes\n");
        } else
            printf("no\n");
    }
    return 0;
}

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你还要判断关键字（保留字）呀，是关键字也不是合法的标识符。

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