关于#python#的问题:编写函数将列表中的元素循环右移k个位置

(1)编写函数将列表中的元素循环右移k个位置。如0123456789，右移三个位置

def move(ls,k):
    n = len(ls)
    while k>0:
        temp = ls[n-1]
        for i in range(n-2,-1,-1):
            ls[i+1] = ls[i]
        ls[0] = temp
        k = k-1
        #print(ls)
    return ls
ls = move([0,1,2,3,4,5,6,7,8,9],3)
file1 = open('test.txt','w')
for i in ls:
    file1.write(str(i) + ' ')
file1.close()

def move(ls, k):
    newls = ls[:]
    n = len(ls)
    for i in range(n):
        ls[i] = newls[(i - k + n) % n] 

string = [0,1,2,3,4,5,6,7,8,9]
move(string, 3)
string = ' '.join([str(s) for s in string])

file = open("d:\\test\\mydata.txt", "w")
file.write(string)
file.close()

给个例子参考：

def move(ls,k):
    while k>0:
        temp = ls[len(ls)-1]
        ls[1:len(ls)] = ls[0:len(ls)-1]
        ls[0] = temp
        k = k-1
    return ls
ls = [0,1,2,3,4,5,6,7,8,9]
ls = move(ls,4)
file = open('d:\\test\\mydata.txt', 'w')
file.write(' '.join(list(map(str, ls))))
file.close()

不用循环，列表切片就可一步做到，除非题目要求用循环。

def move(ls,k):
    return [str(i) for i in (ls[len(ls)-k:] + ls[:len(ls)-k])]

ls = [0,1,2,3,4,5,6,7,8,9]
k = 3
string = ' '.join(move(ls,k))
print(string)
with open(r'd:\test\mydata.txt','w') as f:
    f.write(string)

# 函数的定义
def move(ls, k):
    while k > 0:
        n = len(ls)
        temp = ls[n - 1]
        for i in range(1, n):
            ls[n-i] = ls[n-i - 1]
        ls[0] = temp
        k = k - 1
    return ls

# 文件操作
file = open("D:\\test\mydata.txt", 'w')
list1 = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
move(list1, 3)
file.write(str(list1))
file.close()