比较低级的问题，例如
arr1 = [
{
id:1,
value:xxx
},
{
id:2,
value:xxx
},
]
arr2 = [
{
id:1,
age:16
},
]
先用两个数组中都有的id来判断，如果1中某一项的id和2中的id相同，就把1中的那一项全部替换成2中的值
两层循环就行了吧。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script>
let arr1 = [
{
id: 1,
value: "xxx"
},
{
id: 2,
value: "xxx"
},
]
let arr2 = [
{
id: 1,
age: 16
},
]
function reassign(a1, a2) {
for (let i = 0; i < a1.length; i++) {
for (let j = 0; j < a2.length; j++) {
if (a1[i].id == a2[j].id) {
a1[i] = a2[j];
}
}
}
}
reassign(arr1, arr2);
console.log(arr1, arr2);
</script>
</body>
</html>
arr1.map(v=>{
arr2.map(i=>{
if(v.id== i.id){
v.value = i.age;
}
})
})
console.log(arr1);
var map2={};
arr2.forEach((v,i)=>{
map2[v.id]=v
})
for(var i=0;i<arr1.length;i++){
if(map2[arr1[i].id]){
arr1[i]=map2[arr1[i].id]
}
}
console.log(arr1)
data() {
return {
arr1: [
{
id: 1,
value: 45,
},
{
id: 2,
value: 46,
},
],
arr2: [
{
id: 2,
age: 16,
},
],
};
},
mounted() {
this.arrayAssign();
},
methods: {
arrayAssign() {
for (let i in this.arr1) {
for (let j in this.arr2) {
this.arr1[i].value =
this.arr1[i].id == this.arr2[j].id
? this.arr2[j].age
: this.arr1[i].value;
}
}
console.log(this.arr1);
},
},