后端导入excel不知道怎么接受

public Boolean imp(HttpServletRequest request) throws Exception {
    InputStream inputStream = request.getInputStream();
    ExcelReader reader = ExcelUtil.getReader(inputStream);

代码是这样的 没有用spring框架 MultipartFile这就没用 然后我通过request.getInputStream();获取
用的是hutool 我想问不用MultipartFile用什么来接受excel文件

Hutool只是处理流的工具，它没法映射参数

你是用servlet写的嘛

您好。文件上传需要引入 commons-fileupload-1.4.jar 和 commons-io-2.6.jar 。
然后在后台代码处理文件上传就可以了。

    public String upload(HttpServletRequest request, HttpServletResponse response) {
        ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
        servletFileUpload.setHeaderEncoding("utf-8");
        String filename = null;
        String description = null;
        try {
            List<FileItem> fileItems = servletFileUpload.parseRequest(request);
            for (FileItem fileItem : fileItems) {
                if (fileItem.isFormField()) {
                    description = fileItem.getString("utf-8");
                } else {
                    File dirPath = new File(request.getServletContext().getRealPath("upload"));
                    if (!dirPath.exists()) {
                        dirPath.mkdir();
                    }
                    filename = System.currentTimeMillis() + "-" + fileItem.getName();
                    String path = dirPath + File.separator + filename;
 
                    // IO流处理
                    BufferedInputStream bis = new BufferedInputStream(fileItem.getInputStream());
                    BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(path));
                    byte[] bs = new byte[8192];
                    int size = 0;
                    while ((size = bis.read(bs)) != -1) {
                        bos.write(bs, 0, size);
                    }
                    bos.close();
                    bis.close();
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
 
        FileService fileService = new FileServiceImpl();
        FileInfo newFile = new FileInfo();
        newFile.setFileName(filename);
        newFile.setFilePath(request.getContextPath() + File.separator + "upload" + File.separator + filename);
        newFile.setDescription(description);
        boolean result = false;
        try {
            result = fileService.addFile(newFile);
        } catch (Exception e) {
            e.printStackTrace();
        }
        return result ? "r:/file?methodName=fileList" : "/upload.jsp";
    }

具体看这篇博客：
https://blog.csdn.net/zgphacker2010/article/details/124520408