一个list里面有多个字典，每个字典的key都一样，但是如果出现了不同的value则为其编上序号，请问如何用python实现该功能？

比如原数据是这样的：
list = [
{'a': 10, 'b': 15, 'c': 17},
{'a': 10, 'b': 19, 'c': 28},
{'a': 12, 'b': 16, 'c': 15},
{'a': 10, 'b': 42, 'c': 75}
]

我想要得到这样的结果：
list = [
{'a': 10（1）, 'b': 15, 'c': 17},
{'a': 10（2）, 'b': 19, 'c': 28},
{'a': 12, 'b': 16, 'c': 15},
{'a': 10（3）, 'b': 42, 'c': 75}
]

请问这样用python该如何做到呢？十分感谢回答

list1 = [
{'a': 10, 'b': 15, 'c': 17},
{'a': 10, 'b': 19, 'c': 28},
{'a': 12, 'b': 16, 'c': 15},
{'a': 10, 'b': 42, 'c': 75}
]
for i in range(len(list1)):
    for key, value in list1[i].items():
        count = 1
        temp = list1[i][key]
        for j in range(i+1, len(list1)):
            print(temp, list1[j][key])
            if temp == list1[j][key]:
                if temp == list1[i][key]:
                    list1[i][key] = str(value) + str('({})'.format(count))
                count += 1
                list1[j][key] = str(value) + str('({})'.format(count))
                #break
print(list1)

list = [
{'a': 10, 'b': 15, 'c': 17},
{'a': 10, 'b': 19, 'c': 28},
{'a': 12, 'b': 16, 'c': 15},
{'a': 10, 'b': 42, 'c': 75}
]
avs = [l['a'] for l in list]
bvs = [l['b'] for l in list]
cvs = [l['c'] for l in list]
avs_copy = avs.copy()
for a in avs:
    if avs.count(a)>1:
        num = 1
        for i in range(len(avs_copy)):
            if avs_copy[i] == a:
                avs_copy[i] = str(a)+'('+str(num)+')'
                num += 1
#print(avs_copy)
bvs_copy = bvs.copy()
for b in bvs:
    if bvs.count(b)>1:
        num = 1
        for i in range(len(bvs_copy)):
            if bvs_copy[i] == b:
                bvs_copy[i] = str(b)+'('+str(num)+')'
                num += 1
#print(bvs_copy)
cvs_copy = cvs.copy()
for c in cvs:
    if cvs.count(c)>1:
        num = 1
        for i in range(len(cvs_copy)):
            if cvs_copy[i] == c:
                cvs_copy[i] = str(c)+'('+str(num)+')'
                num += 1
#print(cvs_copy)
for l in range(len(list)):
    list[l]['a'] = avs_copy[l]
    list[l]['b'] = bvs_copy[l]
    list[l]['c'] = cvs_copy[l]
print(list)