我先求出第n个素数值,然后继续往下求第n+1个直到第m个,如果是素数就累加起来,但是提交系统说不对
#include <stdio.h>
int main()
{
int i,p,num=2,count=0,n,m,s;
scanf("%d %d",&n,&m);
while(count<n){
p=1;
for(i=2;i<num;i++){
if(num%i==0){
p=0;
}
break;
}
if(p==1){
count++;
}
s=num;
num++;
}
while(count<m){
p=1;
for(i=2;i<num;i++){
if(num%i==0){
p=0;
}
break;
}
if(p==1){
count++;
s+=num;
}
num++;
}
printf("%d",s);
return 0;
}
#include<stdio.h>
using namespace std;
int main()
{
//int N;
//scanf("%d", &N);
int n, m;
scanf("%d%d",&n,&m);
int sum = 0;
for (int i = n; i <= m; ++i)
{
int count = 0;
for (int j = 2; j < i; ++j)
{
if (i % j == 0)
{
count += 1;
break;
}
}
if (count == 0){
printf("%d为质数\n", i);
sum += i;
}
}
printf("%d", sum);
return 0;
}
#include<stdio.h>
using namespace std;
int main()
{
//int N;
//scanf("%d", &N);
int n, m;
scanf("%d%d",&n,&m);
int sum = 0;
int i = 1;
int N = 2;
while(1)
{
int count = 0;
for (int j = 2; j < N; ++j)
{
if (N % j == 0)
{
count += 1;
break;
}
}
if (count == 0){
printf("%d为质数\n", N);
if(i >= n && i <= m)
{
printf("%d为质数,是第%d个质数\n", N,i);
sum += N;
}
i++;
}
N++;
if (i > m)
break;
}
printf("%d", sum);
return 0;
}
现在,给定两个整数n和m,0<n<=m<=200,你的程序要计算第n个素数到第m个素数之间所有的素数的和,包括第n个素数和第m个素数。