String转LocalDateTime没有效果

前端日期选择器传了"releaseTime":"2022-4-26"给后端，然后出现这个错误

2022-04-26 16:04:31.897  WARN 8364 --- [nio-7070-exec-1] .w.s.m.s.DefaultHandlerExceptionResolver : Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize value of type `java.time.LocalDateTime` from String "2022-4-26": Failed to deserialize java.time.LocalDateTime: (java.time.format.DateTimeParseException) Text '2022-4-26' could not be parsed at index 5; nested exception is com.fasterxml.jackson.databind.exc.InvalidFormatException: Cannot deserialize value of type `java.time.LocalDateTime` from String "2022-4-26": Failed to deserialize java.time.LocalDateTime: (java.time.format.DateTimeParseException) Text '2022-4-26' could not be parsed at index 5<EOL> at [Source: (org.springframework.util.StreamUtils$NonClosingInputStream); line: 4, column: 19] (through reference chain: com.example.wy.entity.Notice["releaseTime"])]

{
    "timestamp": "2022-04-26T08:04:31.905+00:00",
    "status": 400,
    "error": "Bad Request",
    "path": "/notice"
}
之后查找方案加过注解@JsonFormat(pattern = "yyyy-MM-dd")但是还是没有用，有什么办法解决嘛

个人喜好将下面两种注解都加上，一个是前端转后端，一个是后端转前端的。


  /**
     * 创建时间
     */
    @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    //2022-03-22T18:32
    @DateTimeFormat(pattern = "yyyy-MM-dd'T'HH:mm")
    @Column(name = "create_time")
    private Date createTime;
    @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")

"timestamp": "2022-04-26T08:04:31.905+00:00"

这一段中有个字符T，不知道会不会是这个的问题

要这样转换

 LocalDateTime now = LocalDateTime.now();
      

        String format = now.format(DateTimeFormatter.ofPattern("YYYY-MM-dd"));//格式化
        System.out.println(format);

"timestamp": "2022-04-26T08:04:31.905+00:00" 这传错了。这个是时间对象， 应该传时间戳吧。 示例： "timestamp": 1650962512


@PostMapping
      public Boolean save(@RequestBody Notice notice) {
          return noticeService.saveOrUpdate(notice);
      }

接口是这样的，releaseTime是notice类里的，这样定义的：private LocalDateTime releaseTime;

img

注意到这一句，显然4月前面少了0，应该是2022-04-26