该题目要求求出每年的投资数
def f(m, n, l):
print("年数 未来投资值(万)")
for i in range(1, l + 1):
x = m * (1 + n / 100) ** i
print(f"{i:2} {x:.2f}")
m = eval(input())
n = eval(input())
l = eval(input())
f(m, n, l)
count = 0
def f(m,n,l):
b = []
global count
for i in range(1,l+1):
count += 1
x = m* (1+n/100)**i
print(count,"%.2f"%(x))
b.append(x)
return b
a = f(eval(input()),eval(input()),eval(input()))
print(a)
最后一句print删掉
在f(m,n,l)函数的return前面加一句:print(count," ", x)
return也可以删掉