求解答一下c语言想要答案

输入20个数，存放到数组中，求出他们的平均值并输出，输出最大值、最小值及下标。

function avgfunction(int* n,int length){
    int i=0,sum=0,max=0,min=0,maxflag=0,minflag=0;
    float avg;
    for (i=0;i<length;i++){
        sum +=n[i];
        if (min>n[i]){
            min = n[i];
            minflag = i;
        }
        if (max < n[i]){
            max = n[i];
            maxflag = i;
        }
    }
    float result[3];
    result[0] = minflag*1.0;//最小值对应的下标
    result[1] = maxflag*1.0;//最小大值对应的下标
    result[2] = sum/length;//平均值
    return result;
}
void main(){
    int n[20];
    int i=0,j=0,find=0,findflag = 0;
    for( i=0;i<20;i++){
        scanf("%d",&n[i]);
    }
    float value[3] = avgfunction(n,sizeof(n) / sizeof(n[0]));
}

#include <iostream>
#include <sstream>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <string>
#include <cstring>
#include <vector>
#include <stack>
#include <list>
#include <limits.h>

using namespace std;



int main()
{


    int n = 20, maxn = INT_MIN, maxn = INT_MAX, num_PJ = 0, sum = 0, num, max_i, min_i;
    for (int i = 1; i <= n; i++)
    {
        cin >> num;
        sum += num;
        //maxn = max (maxn, num); 这里不能这样写，保存不了下标 
        if (num > maxn)
        {
            maxn = num;
            max_i = i;
        }
        //minn = min (minn, num);
        if (num < minn)
        {
            minn = num;
            min_i = i;
        }
    }
    num_PJ = sum / n;
    printf ("平均值:%d/n最大值:%d 最大值所在位置:%d\n最小值:%d 最小值所在位置:%d\n", num_PJ, maxn, max_i, minn, min_i);
    


    return 0;
}