class Company:
number = 0
def __init__(self,comName,comPreporty):
self.comName = comName
self.comPreporty = comPreporty
self.emList = {"name":[],"age":[],"cost":[]}
Company.number = Company.number +1
def get_company(self):
print(format(self.comName,self.pro))
def recruit(self,empName,age,cost =1000):
self.empName = empName
self.age = age
self.cost = cost
self.emList["name"].append(empName)
self.emList["age"].append(age)
self.emList["cost"].append(cost)
def getEmployeeList(self):
return(self.emList)
c1 =Company("AA","BBBB")
c1.recruit("aa",19)
c1.recruit("bb",16)
c1.recruit("cc",14)
c1.recruit("dd",13)
c1.recruit("ee",12)
我需要用一个叫delete的函数将cc的数据删除
比如
c1.delelte("cc")
然后CC的名字和年龄就删除了,这个功能该如何实现呢?
# -*- coding: UTF-8 -*-
class Company:
number = 0
def __init__(self,comName,comPreporty):
self.comName = comName
self.comPreporty = comPreporty
self.emList = {"name":[],"age":[],"cost":[]}
Company.number = Company.number +1
def get_company(self):
print(format(self.comName,self.pro))
def recruit(self,empName,age,cost =1000):
self.empName = empName
self.age = age
self.cost = cost
self.emList["name"].append(empName)
self.emList["age"].append(age)
self.emList["cost"].append(cost)
def delete(self,empName):
i = self.emList["name"].index(empName)
self.emList["name"].remove(self.emList["name"][i])
self.emList["age"].remove(self.emList["age"][i])
self.emList["cost"].remove(self.emList["cost"][i])
def getEmployeeList(self):
return(self.emList)
c1 = Company("AA","BBBB")
c1.recruit("aa",19)
c1.recruit("bb",16)
c1.recruit("cc",14)
c1.recruit("dd",13)
c1.recruit("ee",12)
print(c1.getEmployeeList())
c1.delete("cc")
print(c1.getEmployeeList())
{'age': [19, 16, 14, 13, 12], 'cost': [1000, 1000, 1000, 1000, 1000], 'name': ['aa', 'bb', 'cc', 'dd', 'ee']}
{'age': [19, 16, 13, 12], 'cost': [1000, 1000, 1000, 1000], 'name': ['aa', 'bb', 'dd', 'ee']}
可以考虑python的析构函数__del__